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Model for $ H_{SB}$: Two-Level System Coupled to Photon Bath in RWA

The microscopic interaction between a two-level atom and a photon bath is via a coupling
$\displaystyle (a_Q + a_Q^{\dagger}) ( \sigma_+ +\sigma_-)= (a_Q + a_Q^{\dagger})\sigma_x,$     (122)

cf. Walls/Milburn, Carmichael, Baym or other quantum optics (quantum mechanics) books. Comparing with our generic form Eq.(7.114),

$\displaystyle H_{SB}(t)\equiv \hat{\bf A}(t) \vec{\sigma}\equiv
\sum_Q \left( {\bf g}_Q(t) a_Q^{\dagger} + {\bf g}_Q^{\dagger}(t) a_Q\right)\vec{\sigma},$

this case would correspond to a (time-independent) coupling vector $ {\bf g}_Q(t)={\bf g}_Q^{\dagger}(t)=(g_Q,0,0)$. Within the RWA, this interaction is further simplified by neglecting the `counter-rotating' terms and by writing
$\displaystyle {\bf g}_Q$ $\displaystyle =$ \begin{displaymath}\frac{1}{2}\gamma_Q\left(
\begin{array}[h]{c}
1\\ -i \\ 0 \end{array}\right), \gamma_Q \mbox{\rm real.}\end{displaymath} (123)

Assuming a free photon bath, the total Hamiltonian then is
$\displaystyle H_{\rm total}$ $\displaystyle \equiv$ $\displaystyle H_S+H_{SB}+H_B$  
  $\displaystyle =$ $\displaystyle H_S+
\sum_Q\gamma_Q(a_Q \sigma_+ +a_Q^{\dagger}\sigma_- ) + \sum_Q \omega_Q a_Q^{\dagger} a_Q.$ (124)


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Next: Mapping onto harmonic oscillator Up: Spontaneous Emission (Atom without Previous: Spontaneous Emission (Atom without   Contents   Index
Tobias Brandes 2004-02-18