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Born-Oppenheimer Approximation

We recall the Born-Oppenheimer Approximation for the total wave function \bgroup\color{col1}$ \Psi(q,X)$\egroup of a molecule, cf. Eq. (V.2.15),
$\displaystyle \Psi(q,X)=\sum_\alpha \phi_\alpha (X) \psi_\alpha(q,X),$     (1.9)

where \bgroup\color{col1}$ q$\egroup stands for the electronic, \bgroup\color{col1}$ X$\egroup for the nuclear coordinates, and the sum is over a complete set of adiabatic electronic eigenstates with electronic quantum numbers \bgroup\color{col1}$ \alpha$\egroup. This form leads to the Schrödinger equation in the adiabatic approximation Eq. (V.2.17),
$\displaystyle \left[\langle \psi_\alpha\vert \mathcal{H}_{\rm n}\vert\psi_\alph...
...ha(X)\right] \vert\phi_\alpha\rangle_n
= \mathcal{E} \vert\phi_\alpha\rangle_n.$     (1.10)

Here, \bgroup\color{col1}$ E_\alpha(X)$\egroup is the potential acting on the nuclei. We now specify the kinetic energy of the nuclear part for a diatomic molecule,
$\displaystyle \mathcal{H}_{\rm n} = \frac{{\bf P}^2}{2M} + \frac{{\bf p}^2}{2\mu}.$     (1.11)

Exercise Check that \bgroup\color{col1}$ \mathcal{H}_{\rm n}=\frac{{\bf p}_1^2}{2m_1} + \frac{{\bf p}_2^2}{2m_2}$\egroup.

The effective nuclear Hamiltonian corresponding to an electronic eigenstate \bgroup\color{col1}$ \alpha$\egroup thus is

$\displaystyle \mathcal{H}_{{\rm n},\alpha} = \langle \psi_\alpha\vert \frac{{\b...
...e \psi_\alpha\vert \frac{{\bf p}^2}{2\mu}\vert\psi_\alpha\rangle + E_\alpha(r),$     (1.12)

which is a sum of a center-of-mass Hamiltonian and a Hamiltonian for the relative motion of the two nuclei. Only the latter is interesting because it contains the potential \bgroup\color{col1}$ E_\alpha(r)$\egroup. Note that both center-of-mass and relative Hamiltonian still contain the geometrical phase terms, cf. Eq. (E.5.2), which however we will neglect in the following.


next up previous contents index
Next: Angular Momentum Up: Hamiltonian Previous: Angular Momentum of Two   Contents   Index
Tobias Brandes 2005-04-26