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Total Spin

One advantage of working with singlets and triplets is the fact that they are spin states of fixed total spin: rthe singlets has total spin \bgroup\color{col1}$ S=0$\egroup, the three triplets have total spin \bgroup\color{col1}$ S=1$\egroup and total spin projections \bgroup\color{col1}$ M=-1,0,1$\egroup:
$\displaystyle \hat{S}^2 \vert S\rangle$ $\displaystyle =$ $\displaystyle \hbar S(S+1) \vert S\rangle, S=0,\quad \hat{S}_z \vert S\rangle = \hbar M \vert S\rangle, M=0$ (2.14)
$\displaystyle \hat{S}^2 \vert T_{-1}\rangle$ $\displaystyle =$ $\displaystyle \hbar S(S+1) \vert T_{-1}\rangle, S=1,\quad \hat{S}_z \vert T_{-1}\rangle = \hbar M \vert T_{-1}\rangle, M=-1$  
$\displaystyle \hat{S}^2 \vert T_{0}\rangle$ $\displaystyle =$ $\displaystyle \hbar S(S+1) \vert T_{0}\rangle, S=1,\quad \hat{S}_z \vert T_{0}\rangle = \hbar M \vert T_{0}\rangle, M=0$  
$\displaystyle \hat{S}^2 \vert T_{+1}\rangle$ $\displaystyle =$ $\displaystyle \hbar S(S+1) \vert T_{+1}\rangle, S=1,\quad \hat{S}_z \vert T_{+1}\rangle = \hbar M \vert T_{+1}\rangle, M=+1.$  

Often the total spin is conserved when we deal with interacting systems. If , for example, the system is in a state that is a linear combination of the three triplets, it has to stay in the sub-space spanned by the triplets and can't get out of it. In that case instead of having a four-dimensional space we just have to deal with a three-dimensional space.


next up previous contents index
Next: Entanglement Up: Properties of Spin-Singlets and Previous: Properties of Spin-Singlets and   Contents   Index
Tobias Brandes 2005-04-26