Piecewise constant potentials in one dimension (5min)

Write down the general solution of

$$\left[-\frac{\hbar^2}{2m}\frac{d^2}{dx^2} + V \right]\psi(x) = {E}\psi({x}),\quad x\in [x_1,x_2]$$ (6)

for $E<V$ and $E>V$. What is the difference between these two cases?