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The \bgroup\color{col1}$ T$\egroup-Matrix

For the following, Economou's `Green's functions in quantum physics' [11] is a useful reference.

We perform perturbation theory for a Hamiltonian

$\displaystyle H = H_0 + V$     (2.12)

by defining two Green's functions (resolvents) of \bgroup\color{col1}$ H$\egroup and \bgroup\color{col1}$ H_0$\egroup as the operators
$\displaystyle G(z) = (z-H)^{-1},\quad G_0(z) = (z-H_0)^{-1}.$     (2.13)

We have
$\displaystyle G = (z-H_0-V)^{-1}= (G_0^{-1}-V)^{-1} = (1-G_0V)^{-1} G_0$     (2.14)

and by expanding in \bgroup\color{col1}$ V$\egroup we obtain the Dyson equation
$\displaystyle G = G_0 + G_0VG_0 + G_0VG_0VG_0 + ... = G_0 + G_0VG.$     (2.15)

We can express the full Green's function \bgroup\color{col1}$ G$\egroup in terms of the free Green's function \bgroup\color{col1}$ G_0$\egroup and the \bgroup\color{col1}$ T$\egroup-matrix,
$\displaystyle G$ $\displaystyle =$ $\displaystyle G_0 + G_0VG_0 + G_0VG_0VG_0 + G_0VG_0VG_0VG_0+...$  
  $\displaystyle =$ $\displaystyle G_0 + G_0 \left[ V + VG_0V + VG_0VG_0V + ... \right ]G_0 \equiv G_0 + G_0T G_0$  
$\displaystyle T(z)$ $\displaystyle \equiv$ $\displaystyle V + VG_0(z) V + VG_0(z)VG_0(z)V + ...$ (2.16)

We recognize that \bgroup\color{col1}$ T(z)$\egroup plays the role of an effective, \bgroup\color{col1}$ z$\egroup-dependent potential, the knowledge of which is sufficient to calculate the full Green's function \bgroup\color{col1}$ G$\egroup.


next up previous contents index
Next: Two molecules Up: Effective Interaction between Molecules Previous: From Classical to Quantum   Contents   Index
Tobias Brandes 2005-04-26