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For the following, Economou's `Green's functions in quantum physics' [11] is a useful reference.
We perform perturbation theory for a Hamiltonian
 |
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(2.12) |
by defining two Green's functions (resolvents) of
and
as the operators
 |
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(2.13) |
We have
 |
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(2.14) |
and by expanding in
we obtain the Dyson equation
 |
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(2.15) |
We can express the full Green's function
in terms of the free Green's function
and the
-matrix,
We recognize that
plays the role of an effective,
-dependent potential, the knowledge of which is sufficient to calculate the full Green's function
.
Next: Two molecules
Up: Effective Interaction between Molecules
Previous: From Classical to Quantum
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Tobias Brandes
2005-04-26