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The first order term in
in our expansion Eq. (IX.2.20) is
 |
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(2.23) |
This is just given by the expectation value of the terms that make up the interaction potential
, Eq. (IX.2.22).
For the dipole-dipole interaction, this gives
 |
|
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(2.24) |
Since the first order is linear in the interaction potential operator
, the effective
is essential just the
with all operators replaced by their expectation values.
This is the static dipole-dipole interaction between the molecules. The corresponding force between the two dipoles is
 |
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(2.25) |
Its form is just as in the classical dipole-dipole interaction. However, this interaction is zero if one of the expectation values of the dipole moment operators vanishes. Such molecules are said to have no static dipole moment.
Next: Second oder term: (London)
Up: Effective Potentials
Previous: Two molecules
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Tobias Brandes
2005-04-26