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First oder term: static dipole-dipole interaction

The first order term in \bgroup\color{col1}$ V_{\rm eff} $\egroup in our expansion Eq. (IX.2.20) is
$\displaystyle V_{\rm eff}^{(1)} = \sum_i \sum_{k} p_k \langle k\vert v_i \vert ...
...'\vert v_i' \vert k'\rangle
= \sum_i \langle v_i \rangle \langle v_i' \rangle .$     (2.23)

This is just given by the expectation value of the terms that make up the interaction potential \bgroup\color{col1}$ = \sum_i v_i \otimes v_i' $\egroup, Eq. (IX.2.22). For the dipole-dipole interaction, this gives
$\displaystyle V_{\rm eff}^{(1)}({\bf R}) = \frac{\langle {\bf d}\rangle \langle...
...ngle {\bf d}\rangle ) ({\bf R}\langle {\bf d}'\rangle ) }{\vert{\bf R}\vert^5}.$     (2.24)

Since the first order is linear in the interaction potential operator \bgroup\color{col1}$ V$\egroup, the effective \bgroup\color{col1}$ V_{\rm eff}^{(1)}$\egroup is essential just the \bgroup\color{col1}$ V$\egroup with all operators replaced by their expectation values. This is the static dipole-dipole interaction between the molecules. The corresponding force between the two dipoles is
$\displaystyle {\bf F}_{\rm eff}^{(1)}({\bf R})= - {\bf\nabla} V_{\rm eff}^{(1)}({\bf R}).$     (2.25)

Its form is just as in the classical dipole-dipole interaction. However, this interaction is zero if one of the expectation values of the dipole moment operators vanishes. Such molecules are said to have no static dipole moment.


next up previous contents index
Next: Second oder term: (London) Up: Effective Potentials Previous: Two molecules   Contents   Index
Tobias Brandes 2005-04-26