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This follows from Eq.(7.11) and (7.10) by taking the trace over
the bath,
![$\displaystyle \fbox{$ \begin{array}{rcl} \displaystyle \frac{d}{dt} \tilde{\rho...
... dt'{\rm Tr}_B [\tilde{V}(t),[\tilde{V}(t'),\tilde{\chi}(t')]].
\end{array}$\ }$](img72.png) |
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Tobias Brandes
2004-02-18