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The parity

For symmetric potentials $ V(x)=V(-x)$, the Schrödinger equation has an important property: If $ \psi(x)$ is a solution of $ \hat{H}\psi(x)=E \psi(x)$, then also $ \psi(-x)$ is a solution with the same $ E$, i.e. $ \hat{H}\psi(-x)=E \psi(-x)$ (replace $ -x \to x$ and note that $ \partial_x^2 = \partial_{-x}^2$. Since $ \hat{H}$ is linear, also linear combinations of solutions with the same eigenvalue $ E$ are solutions with eigenvalue $ E$, in particular the symmetric (even) and anti symmetric (odd) linear combinations
$\displaystyle \psi_e(x):=\frac{1}{\sqrt{2}}[\psi(x)+\psi(-x)],\quad
\psi_o(x):=\frac{1}{\sqrt{2}}[\psi(x)-\psi(-x)].$     (107)

These are the solutions with even (e) and odd (o) parity, respectively.



Tobias Brandes 2004-02-04