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The parameter in the Gauss function determines its width. A broad wave packet in coordinate
() space
corresponds to a narrow distribution of wave vectors .
What happens in the limit
? In coordinate space, this would correspond to an extremely sharp
wave packet around that could serve as a model for a particle localized at .
We define
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(48) |
As an ordinary function, this is a somewhat strange mathematical object because it is zero for all , but
infinite for . However, it has the useful property that for any (reasonably well-behaving) function
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(49) |
For example, multiplication of with
and integration over the whole -axis gives the value
of at . Such an operation is called a functional, that is a mapping
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(50) |
that puts a
whole function to a (complex or real) number. Nevertheless, for historical reasons physicists call this
object a delta-function. Remember that is only defined as in (1.49), that is
by integration over a function (`test-function') .
Another very useful property is the Fourier transform of the Delta-function:
We recall our definition
Now, comparing with the definition of the Delta function, Eq.(1.49), we recognise
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(52) |
The delta function is thus a superposition of all plane waves; the corresponding
distribution of -values
in -space is `extremely broad', that is uniform from to .
Note that we can also obtain the result
from the Fourier transform
of the Gauss function , Eq. (1.46), in the limit
.
Next: * Partial Differential Equations
Up: Fourier Transforms and the
Previous: Math: Gauss function
  Contents
Tobias Brandes
2004-02-04